Open AccessRelation between Two Operator Inequalities <img src="http://latex.codecogs.com/gif.latex?f(B^{\frac{1}{2}}AB^{\frac{1}{2}})\geq&space;B^{-1}" title="f(B^{\frac{1}{2}}AB^{\frac{1}{2}})\geq B^{-1}" /> and <img src="http://latex.codecogs.com/gif.latex?A^{-1}\geq&space;g(A^{\frac{1}{2}}BA^{\frac{1}{2}})" title="A^{-1}\geq g(A^{\frac{1}{2}}BA^{\frac{1}{2}})" />
Author(s) -
Muhammad Ilyas,
Reyaz Ahmad,
Shadab Ilyas
Publication year - 2015
Publication title -
advances in pure mathematics
Language(s) - English
Resource type - Journals
eISSN - 2160-0368
pISSN - 2160-0384
DOI - 10.4236/apm.2015.52012
Subject(s) - mathematics , combinatorics , operator (biology) , chemistry , biochemistry , repressor , transcription factor , gene