z-logo
Premium
The curvature invariant for a class of homogeneous operators
Author(s) -
Misra Gadadhar,
Shyam Roy Subrata
Publication year - 2009
Publication title -
proceedings of the london mathematical society
Language(s) - English
Resource type - Journals
SCImago Journal Rank - 1.899
H-Index - 65
eISSN - 1460-244X
pISSN - 0024-6115
DOI - 10.1112/plms/pdp011
Subject(s) - mathematics , covariant derivative , covariant transformation , equivalence class (music) , unitary state , curvature , pure mathematics , invariant (physics) , operator (biology) , vector bundle , equivalence (formal languages) , mathematical analysis , mathematical physics , geometry , biochemistry , chemistry , repressor , political science , transcription factor , law , gene
For an operator T in the class B n (Ω), introduced by Cowen and Douglas, the simultaneous unitary equivalence class of the curvature and the covariant derivatives up to a certain order of the corresponding bundle E T determine the unitary equivalence class of the operator T . In a subsequent paper, the authors ask if the simultaneous unitary equivalence class of the curvature and these covariant derivatives are necessary to determine the unitary equivalence class of the operator T ∈ B n (Ω). Here we show that some of the covariant derivatives are necessary. Our examples consist of homogeneous operators in B n (). For homogeneous operators, the simultaneous unitary equivalence class of the curvature and all its covariant derivatives at any point w in the unit disc are determined from the simultaneous unitary equivalence class at 0. This shows that it is enough to calculate all the invariants and compare them at just one point, say 0. These calculations are then carried out in number of examples. One of our main results is that the curvature along with its covariant derivative of order (0, 1) at 0 determines the equivalence class of generic homogeneous Hermitian holomorphic vector bundles over the unit disc.

This content is not available in your region!

Continue researching here.

Having issues? You can contact us here