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Synthesis and Luminescence Properties of BaMoO 4 :Sm 3+ Phosphors
Author(s) -
Xia Zhiguo,
Chen Daimei
Publication year - 2010
Publication title -
journal of the american ceramic society
Language(s) - English
Resource type - Journals
SCImago Journal Rank - 0.9
H-Index - 196
eISSN - 1551-2916
pISSN - 0002-7820
DOI - 10.1111/j.1551-2916.2009.03574.x
Subject(s) - phosphor , tetragonal crystal system , materials science , luminescence , ion , analytical chemistry (journal) , doping , emission spectrum , irradiation , ultraviolet , spectral line , crystal structure , crystallography , chemistry , optoelectronics , physics , organic chemistry , chromatography , astronomy , nuclear physics
BaMoO 4 :Sm 3+ phosphor system with a tetragonal structure was synthesized via a high‐temperature solid‐state method. The charge compensated behaviors, 2Ba 2+ →Sm 3+ +M + , where M + is a monovalent cation like Li + , Na + , and K + acting as a charge compensator, were investigated in this paper. It has been found that BaMoO 4 :Sm 3+ phosphor by doping with K + ions show greatly enhanced reddish orange emission compared with pure BaMoO 4 :Sm 3+ sample. Investigation on Sm 3+ and K + concentration‐dependent emission spectra indicated that Ba 0.84 MoO 4 :0.08Sm 3+ ,0.12K + phosphor exhibited the strongest reddish orange emission with a CIE values of x =0.55 and y =0.43. After irradiation under the 402 nm ultraviolet (UV) excitation, three emission peaks centered at 561, 598, and 642 nm corresponding to the 4 G 5/2 to 6 H J ( J =5/2, 7/2, 9/2) emission lines of Sm 3+ were obviously observed, and the lifetimes of three emissions ( 4 G 5/2 → 6 H J =5/2, 7/2, 9/2 ) have been calculated based on the measured decay curves.