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Elongation factor 3 (EF‐3) from Candida albicans shows both structural and functional similarity to EF‐3 from Saccharomyces cerevisiae
Author(s) -
Colthurst D. R.,
Schauder B. S.,
Hayes M. V.,
Tuite M.F.
Publication year - 1992
Publication title -
molecular microbiology
Language(s) - English
Resource type - Journals
SCImago Journal Rank - 1.857
H-Index - 247
eISSN - 1365-2958
pISSN - 0950-382X
DOI - 10.1111/j.1365-2958.1992.tb02168.x
Subject(s) - biology , candida albicans , saccharomyces cerevisiae , corpus albicans , gene , open reading frame , microbiology and biotechnology , genetics , peptide sequence
Summary As with many other fungi, including the budding yeast Saccharomyces cerevisiae, the dimorphic fungus Candida albicans encodes the novel translation factor, elongation factor 3 (EF‐3). Using a rapid affinity chromatography protocol, EF‐3 was purified to homogeneity from C. albicans and shown to have an apparent molecular mass of 128 kDa. A polyclonal antibody raised against C. albicans EF‐3 also showed cross‐reactivity with EF‐3 from S. cerevisiae. Similariy, the S. cerevisiae TEF3 gene (encoding EF‐3) showed cross‐hybridization with genomic DNA from C. albicans in Southern hybridization anaiysis, demonstrating the existence of a single gene closely related to TEF3 in the C. albicans genome. This gene was cloned by using a 0.7 kb polymerase chain reaction‐amplified DNA fragment to screen a C. albicans gene library. DNA sequence analysis of 200 bp of the cloned fragment demonstrated an open reading frame showing 51% predicted amino acid identity between the putative C. albicans EF‐3 gene and its S. cerevisiae counterpart over the encoded 65‐aminoacid stretch. That the cloned C. aibicans sequence did indeed encode EF‐3 was confirmed by demonstrating its ability to rescue an otherwise non‐viable S. cerevisiae tef3:HIS3 null mutant. Thus EF‐3 from C. albicans shows both structural and functional similarlity to EF‐3 from S. cerevisiae .