Open Access
Proportion of genes survived in offspring conditional on inheritance of flanking markers.
Author(s) -
SunWei Guo
Publication year - 1994
Publication title -
genetics
Language(s) - English
Resource type - Journals
SCImago Journal Rank - 2.792
H-Index - 246
eISSN - 1943-2631
pISSN - 0016-6731
DOI - 10.1093/genetics/138.3.953
Subject(s) - biology , genetics , identity by descent , gene , chromosome , inheritance (genetic algorithm) , human genome , offspring , genome , markov chain , mathematics , allele , haplotype , statistics , pregnancy
In mammalian genetics and perhaps in human genetics as well, it is an interesting question as to how many offspring are needed in order to have a desired chance of preserving part of the entire genome of an individual. A more practical and perhaps more important question is: given k children and DNA marker data on a particular region of interest, what proportion of one's genes has been actually passed on to his children? To answer this question, I define the concept of identity by descent proportion, or IBDP for short. The IBDP is defined to be the proportion of genetic material shared identical by descent by a group of relatives in a specified chromosomal region. I provide a novel approach to computing the mean and variance of IBDP for k (> or = 2) half-sibs based on marker data, thus providing a means to compute the mean and variance of proportion of genes survived. I first show that each chromosome in an offspring can be represented by a two-state Markov chain, with the time parameter being the map distance along the chromosome. On this basis, I will show that IBDP can be written as a stochastic integral and that the computation of the EIBDP can be reduced to evaluating an integral of some elementary functions. Numerical examples are provided to illustrate the calculation.