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Profile Matching Algorithm in Determining the Position of Colleagues
Author(s) -
Irwan Sugiarto,
G. S. M. Diyasa,
Muhammad Idhom
Publication year - 2021
Publication title -
journal of physics. conference series
Language(s) - English
Resource type - Journals
SCImago Journal Rank - 0.21
H-Index - 85
eISSN - 1742-6596
pISSN - 1742-6588
DOI - 10.1088/1742-6596/1844/1/012026
Subject(s) - ranking (information retrieval) , matching (statistics) , core (optical fiber) , position (finance) , value (mathematics) , selection (genetic algorithm) , variable (mathematics) , algorithm , computer science , blossom algorithm , process (computing) , operations research , sequence (biology) , data mining , engineering , mathematics , artificial intelligence , machine learning , statistics , business , telecommunications , mathematical analysis , finance , biology , genetics , operating system
The selection of a colleague or business is a process that must be thoroughly detailed, this will affect the development of a company. A decision support system is a solution to shorten a leader or staff in the cooperation section, where a company has several categories to be applied to the decision support system. The Profile Matching algorithm is an algorithm that is applied to build a system that can help provide a choice of potential partners or colleagues / business partners in certain companies, this profile matching algorithm requires many variables to be able to calculate the proposed output from the ranking value later. There are Core Factors and Secondary Factors, in the case of this discussion there are 3 prospective partners who are calculated for this profile matching algorithm. The distribution of variable data entered into the Profile Matching Algorithm, there are 8 categories, there is 4 categories included Core Factor and 4 categories included in the Secondary Factor, more then results of the GAP calculation show that the ranking value gets a maximum value of 4 (Partner 3), sequence No.2 is M1 and the last one M2 with each GAP value is 3.5.

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