Finally Fulfilling Wade’s Rules: The  C  4 v   Symmetric Polycation Bi 9  5+  in the Polar Structure of Bi 18 Sn 7 Br 24  = (Bi 9  5+ ) 2 [Sn 7 Br 24  10– ] | Zendy

Wahl Bernhard | Zendy; Ruck Michael | Zendy

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Finally Fulfilling Wade’s Rules: The C 4 v Symmetric Polycation Bi 9 5+ in the Polar Structure of Bi 18 Sn 7 Br 24 = (Bi 9 5+ ) 2 [Sn 7 Br 24 10– ]

Author(s) -

Wahl Bernhard,

Ruck Michael

Publication year - 2010

Publication title -

zeitschrift für anorganische und allgemeine chemie

Language(s) - English

Resource type - Journals

SCImago Journal Rank - 0.354

H-Index - 66

eISSN - 1521-3749

pISSN - 0044-2313

DOI - 10.1002/zaac.200900314

Subject(s) - bismuth , tetragonal crystal system , crystallography , square antiprism , homonuclear molecule , crystal structure , group (periodic table) , chemistry , tin , lattice (music) , space group , x ray crystallography , ion , diffraction , physics , molecule , quantum mechanics , organic chemistry , lanthanide , acoustics

The bismuth rich bromidostannate(II) Bi 18 Sn 7 Br 24 = (Bi 9 5+ ) 2 [Sn 7 Br 24 10– ] was crystallized from a melt of bismuth, tin, and BiBr 3 . X‐ray diffraction on a single crystal revealed a polar, tetragonal structure (space group I 4 cm , no. 108) with lattice parameters a = 1323.70(5) pm and c = 1816.86(8) pm at 110(5) K. In agreement with Wade’s rules and quantum chemical calculations, the homonuclear nido cluster Bi 9 5+ is a monocapped square antiprism (point group C 4 v ). The anions of the bromidostannate(II) groups mainly comply with the pseudosymmetry of the space group I 4/ mcm and thereby affect substantial disorder of the Sn II cations.

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