Apparently Regular Octahedral Coordination of Ag(II) in IF 6 [Ag(SbF 6 ) 3 ]

The crystal structure of IF 6 [Ag(SbF 6 ) 3 ] has been determined by X‐ray single crystal and X‐ray powder diffraction analysis. The structure consists from [Ag(SbF 6 ) 3 ] – chains and [IF 6 ] + cations placed between them. Ag 2+ is found in regular octahedral coordination of six fluorine atoms [Ag–F = 6 × 2.170(12) Å]. EXAFS analysis of Jahn–Teller distortions in IF 6 [Ag(SbF 6 ) 3 ] shows that Ag 2+ surrounding is elongated octahedral at room temperature. EXAFS signals are fitted with four short and two long Ag–F distances [4 × 2.11(1) Å; 2 × 2.40(2) Å]. This result is in apparent contradiction with X‐ray diffraction studies where the [AgF 6 ] moiety appears to be a regular octahedra. The Raman spectrum of IF 6 [Ag(SbF 6 ) 3 ] is in agreement with the presence of regular IF 6 and deformed SbF 6 groups.