Reaktion von Decaboran mit dem Phosphaalkin PC t Bu

Reaction of Decaborane with the Phosphaalkyne PC t Bu The borane B 10 H 12 (SMe 2 )2 ( 1 ) reacts with the phosphaalkyne P°C t Bu to form the product [B 10 H 11 (SMe 2 )][C( t Bu)‐PH](B 10 H 12 ) ( 2 ), in which two B 10 units are linked by a HP‐C t Bu bridge. The B 10 unit B is simply bound to the bridge C atom, whereas the B 10 unit A is bound to both bridging atoms, P and C, by atom B6 and, moreover, to the P atom by atom B5. The solvate complex 2 · CH 2 Cl 2 crystallizes in the space group P ¯.