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Points of narrowness and uniformly narrow operators
Author(s) -
A. I. Gumenchuk,
I. Krasikova,
M. M. Popov
Publication year - 2017
Publication title -
carpathian mathematical publications
Language(s) - English
Resource type - Journals
SCImago Journal Rank - 0.63
H-Index - 4
eISSN - 2313-0210
pISSN - 2075-9827
DOI - 10.15330/cmp.9.1.37-47
Subject(s) - mathematics , counterexample , disjoint sets , banach space , pure mathematics , fixed point , space (punctuation) , linear operators , function (biology) , measure (data warehouse) , hilbert space , operator theory , discrete mathematics , mathematical analysis , linguistics , philosophy , evolutionary biology , biology , database , computer science , bounded function
It is known that the sum of every two narrow operators on $L_1$ is narrow, however the same is false for $L_p$ with $1 0$ there exists a decomposition $e = e' + e''$ to disjoint elements such that $\|S(e') - S(e'')\| < \varepsilon$ and $\|T(e') - T(e'')\| < \varepsilon$. The standard tool in the literature to prove the narrowness of the sum of two narrow operators $S+T$ is to show that the pair $S,T$ is uniformly narrow. We study the question of whether every pair of narrow operators with narrow sum is uniformly narrow. Having no counterexample, we prove several theorems showing that the answer is affirmative for some partial cases.

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