z-logo
open-access-imgOpen Access
INTERVAL OSCILLATION CRITERIA FOR SECOND-ORDER DELAY AND ADVANCED DIFFERENCE EQUATIONS
Author(s) -
Ayşe Feza Güvenilir
Publication year - 2009
Publication title -
communications faculty of science university of ankara series a1mathematics and statistics
Language(s) - English
Resource type - Journals
ISSN - 1303-5991
DOI - 10.1501/commua1_0000000646
Subject(s) - oscillation (cell signaling) , interval (graph theory) , mathematics , order (exchange) , dynamic equation , mathematical analysis , combinatorics , control theory (sociology) , physics , computer science , nonlinear system , chemistry , control (management) , finance , artificial intelligence , economics , biochemistry , quantum mechanics
Interval oscillation criteria are established for second-order di¤erence equations in the form (k (n) x(n))+p (n)x (g (n))+q (n) jx (g (n))j 1 x (g (n))=e (n) ; (E ) where n n0; n0 2 N = f0; 1; :::g; > 1; k; p; q; e and g are sequences of real numbers; k (n) > 0 is nondecreasing; g(n) is nondecreasing, limn!1 g(n) =1: Several oscillation criteria are given for equation (E ) considered as to separate delay and advanced di¤erence equations when g(n) < n and g(n) > n respectively. Illustrative examples are included. 1. Introduction We consider second-order di¤erence equations of the form, (k (n) x(n))+p (n)x (g (n))+q (n) jx (g (n))j 1 x (g (n)) = e(n) (E ) where n n0; n0 2 N = f0; 1; :::g; > 1; k; p; q; e and g are sequences of real numbers; k (n) > 0 is nondecreasing; g(n) is nondecreasing, limn!1 g(n) =1: is the forward di¤erence operator de…ned by x(n) = x(n+1) x(n): As is customary, we assume that solutions of (E ) exist on some set fn0; n0+1; :::g: For the theory of existence of solutions of such equations, we refer [1]: A nontrivial solution fx(n)g of (E ) is called oscillatory if for any given ~ n0 n0 there exists an integer n1 ~ n0 such that x(n1)x(n1 + 1) 0, otherwise it is called nonoscillatory. The equation will be called oscillatory if every solution is oscillatory. Taking g(n) as (n) with (n) < n and limn!1 (n) = 1; = , equation (E ) is considered as a delay di¤erence equation (k (n) x(n))+p1 (n)x ( (n))+q1 (n) jx ( (n))j 1 x ( (n))=e (n) (ED) Received by the editors April 16, 2009, Accepted: June. 16, 2009. 2000 Mathematics Subject Classi…cation. 34K11, 34C10. Key words and phrases. Interval oscillation, Second-order, Delay argument, Advanced argument, Oscillatory. c 2009 Ankara University 39 40 A. FEZA GÜVENILIR or taking g(n) as (n) with (n) > n and = ;equation (E ) is considered as an advanced di¤erence equation (k (n) x(n))+p2 (n)x ( (n))+q2 (n) jx ( (n))j 1 x ( (n))=e (n) : (EA) In literature, there isn’t enough work dealing with the oscillation of di¤erence equations (ED) and (EA): Equation (E ); when k(n) 1; p (n) 0 or q (n) 0 and g(n) = n; n+ 1; n has been studied by many authors, see [6; 7; 12; 13; 15] and the references cited therein. Using Riccatti tecnique, Saker[9] obtained some oscillation criteria for forced Emden-Fowler superlinear di¤erence equation of the form x(n)+q (n)x (n+ 1)=e(n) when q(n) and e(n) are sequences of positive real numbers. Zhang and Chen [14] established some oscillation criteria x(n)+q (n) f (x (n+ 1))=0 whenf is nondecreasing and uf(u) > 0 for u 6= 0. The …rst result concerning the interval oscillation of (E ) when g(n) = n + 1; q(n) 0; e(n) 0 has been studied by Kong and Zettl [7]: They have applied the telescoping principle for equation of the form (k (n) x(n))+p (n)x (n+ 1)=0: Recently, Güvenilir and Zafer [4] has presented some su¢ cient conditions about oscillation of second-order di¤erential equation (k(t)x0(t))0+p (t) jx ( (t))j 1 x ( (t))+q (t) jx ( (t))j 1 x ( (t))=e (t) : (1:1) where n 0. Later, in [2] Anderson generalized the results of Güvenilir and Zafer [4] to the dynamic equation (kx ) (t)+p (t) jx ( (t))j 1 x ( (t))+q (t) jx ( (t))j 1 x ( (t))=e (t) (1:2) where n 0 for arbitrary time scales. In this work, our purpose is to derive interval oscillation criteria as discrete analogues of the ones contained [3]: The di¤erence between (E ) and (1:2) is the appearence of both linear and nonlinear terms. Therefore, the results in [2] fails to apply for (E ): For our purpose, we denote D (ak; bk) = fu : u (ak) = u (bk) = 0; k = 1; 2; u (n) 6 0; n 2 N(ak; bk)g ; where N(ak; bk) = fak; ak + 1; :::; bkg: As in [4]; we de…ne P (n) = ( 1) 1 q (n) je (n)j 1= : (1:3) INTERVAL OSCILLATION CRITERIA FOR SECOND-ORDER 41 2. Delay Difference Equations Suppose that for any given N 0 there exist a1,a2,b1,b2 N such that a1 < b1; a2 < b2 and p1 (n) 0; q1(n) 0 for n 2 N( (a1) ; b1) [ N( (a2) ; b2): (2:1) Let e (n) satis…es e (n) 0; for n 2 N( (a1) ; b1) e (n) 0; for n 2 N( (a2) ; b2): (2:2) Theorem 2.1. Suppose that (2:1) and (2:2) hold. If there exist an H1 2 D (ai; bi) ; i = 1; 2; such that bi 1 X n=ai H 1 (n+ 1) (p1 (n) + P (n)) (n) (ai) n+ 1 (ai) ( H1 (n))k (n) 0; (2:3) for i = 1; 2; then (ED) is oscillatory. Proof. To get a contradiction, let us suppose that x (n) is a nonoscillatory solution of equation (ED) : First, assume x (n) > 0, x ( (n)) > 0 for all n n1 for some n1 > 0: We may say F (x) = Ax ( 1) A1= B 1= x+B 0 for x 2 [0;1) (2:4) where A, B are nonnegative constants and > 1; [10]: If we choose A = q1(t), B = e(n) and = in (2:4), we have q1 (t)x ( (n)) e (n) ( 1) 1 q1 (n) 1 je (n)j 1 x ( (n)) : (2:5) for n 2 N( (a1); b1) See also [8; 10]: De…ne w (n) = k (n) x (n) x (n) ; n n1; n1 > 0: (2:6) In view of (ED) ; we see that w (n) = x(n) k(n)x(n+1)w 2 (n) + p1 (n) x( (n)) x(n+1) + [q1 (n)x ( (n)) e (n)] 1 x(n+1) : (2:7) Using (2:1) and (2:5), we see from (2:7) that w (n) x(n) k (n)x(n+ 1) w (n) + [p1 (n) + P (n)] x ( (n)) x (n+ 1) ; n 2 N( (a1) ; b1): Moreover x(n+ 1) = x(n) + x(n); 42 A. FEZA GÜVENILIR x(n+ 1) x(n) = 1 + x(n) x(n) and then x(n) k (n)x(n+ 1) = 1 k (n) w (n) : Therefore w (n) 1 k (n) w (n) 2 (n) + [p1 (n) + P (n)] x ( (n)) x (n+ 1) ; n 2 N( (a1) ; b1): (2:8) Now by the Mean Value Theorem in [1] x(n) x ( (a1)) k ( ) x ( ) k ( ) (n (a1)) for some 2 N( (a1) ; n): From which, for any n 2 N(a1; b1),we have x(n) x (n) (n (a1)); n 2 N(a1; b1) and hence, x (n) x(n) 1 n (a1) ; n 2 N(a1; b1): Moreover, following the arguments in [2], since x(m) x (m) (m (a1)) 0; m 2 N( (n); n+ 1); n 2 N(a1; b1) we have x(m) x (m) (m (a1)) x(m)x(m+ 1) 0: Therefore, ( m (a1) x(m) ) 0: It follows that

The content you want is available to Zendy users.

Already have an account? Click here to sign in.
Having issues? You can contact us here
Accelerating Research

Address

John Eccles House
Robert Robinson Avenue,
Oxford Science Park, Oxford
OX4 4GP, United Kingdom