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Compoiste Neutrinos and Double Beta Decay
Author(s) -
E. Takasugi
Publication year - 1995
Publication title -
progress of theoretical physics
Language(s) - English
Resource type - Journals
eISSN - 1347-4081
pISSN - 0033-068X
DOI - 10.1143/ptp.94.1097
Subject(s) - physics , particle physics , majorana , neutrino , double beta decay , higgs boson , excited state , sterile neutrino , nuclear physics , electron neutrino , coupling constant , neutrino oscillation
Neutrinoless double beta decay $(\b\b)_{0\nu}$ occurs through the magneticcoupling of dimension five, $\lambda_W^{(\nu*)}/m_{\nu*}$, among the excitedelectron neutrino $\nu^*$, electron and $W$ boson if $\nu^*$ is a massiveMajorana neutrino. If the coupling is not small, i.e., $\lambda_W^{(\nu*)}>1$the mass of the excited neutrino must not be gless than the $Z$ boson mass,$m_Z$. Since $\nu^*$ contributes in the $(\b\b)_{0\nu}$ decay as a vertualstate, this decay will give an oppotunity to explore the much heavier massregion of $\nu^*$. In this paper, we present the decay formula of $(\b\b)_{0\nu}$ decay throughthe $\nu^*$ exchange and discuss the constraint on the coupling constant andthe mass of the excited neutrino. By comparing the recent data for ${}^{76}$Ge,we find $\lambda_W^{(\nu*)}({1\rm TeV}/m_{\nu*})) (m_N/{1\rm TeV})^{\frac 12}<4.1\cdot 10^{-3}$ where $m_N$ is the Majorana mass of the excited electronneutrino. If $m_N=m_{\nu*}$ and $\lambda_W^{(\nu*)}>1$, we find the mass boundfor the excited Majorana neutrino as $m_{\nu^*} > 5.9\cdot 10^4$TeV. In order to obtain the constraint on the composite scale $\Lambda$, we haveto specify the model. For the mirror type and the homodoublet type models,$\lambda_W^{(\nu*)}/m_{\nu*}=f/(\sqrt 2 \Lambda)$ where $f$ is the relativestrength of gauge couplings. Then, we obtain $\Lambda > 170 f (m_N/{1\rmTeV})^{\frac 12}$TeV. For the sequential type model,$\lambda/m_{\nu*}=fv/(\sqrt 2 \Lambda^2)$ where $v$ is the vacuum expectationvalue of the dopublet Higgs boson, i.e., $v=$250GeV. In this model, we find$\Lambda > 6.6 f^{\frac 12} (m_N/{1\rm TeV})^{\frac 14}$TeV

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