On a Calderón Problem in Frequency Differential Electrical Impedance Tomography
Author(s) -
Sunghwan Kim,
Alexandru Tamasan
Publication year - 2013
Publication title -
siam journal on mathematical analysis
Language(s) - English
Resource type - Journals
SCImago Journal Rank - 1.882
H-Index - 92
eISSN - 1095-7154
pISSN - 0036-1410
DOI - 10.1137/130904739
Subject(s) - nabla symbol , omega , lambda , mathematical analysis , mathematics , boundary (topology) , electrical impedance tomography , physics , combinatorics , geometry , mathematical physics , electrical impedance , quantum mechanics
Recent research in electrical impedance tomography produced images of biological tissue from frequency differential boundary voltages and corresponding currents. Physically one is to recover the electrical conductivity $\sigma$ and permittivity $\epsilon$ from the frequency differential boundary data. Let $\gamma=\sigma+i\omega\epsilon$ denote the complex admittivity, $\Lambda_{\gamma}$ be the corresponding Dirichlet-to-Neumann map, and $\frac{d\Lambda_{\gamma}}{d\omega}|_{\omega=0}$ be its frequency differential at $\omega=0$. If $\sigma\in C^{1,1}(\overline\Omega)$ is constant near the boundary and $\epsilon\in C^{1,1}_0(\Omega)$, we show that $\frac{d\Lambda_{\gamma}}{d\omega}|_{\omega=0}$ uniquely determines $\nabla\cdot(\nabla\epsilon-\epsilon\nabla\ln\sigma)/\sigma$ inside $\Omega$. In addition, if $\Lambda_{\gamma}|_{\omega=0}$ is also known, then $\epsilon$ and $\sigma$ can be reconstructed inside. The method of proof uses the complex geometrical optics solutions.
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