(1 Z )‐Phthalazin‐1(2 H )‐one isopropylidenehydrazone | Zendy

Büyükgüngör Orhan | Zendy; Odabaşoğlu Mustafa | Zendy; Vijesh A. M. | Zendy; Yathirajan H. S. | Zendy

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(1 Z )‐Phthalazin‐1(2 H )‐one isopropylidenehydrazone

Author(s) -

Büyükgüngör Orhan,

Odabaşoğlu Mustafa,

Vijesh A. M.,

Yathirajan H. S.

Publication year - 2007

Publication title -

acta crystallographica section e

Language(s) - English

Resource type - Journals

ISSN - 1600-5368

DOI - 10.1107/s1600536807044807

Subject(s) - dihedral angle , substituent , hydrogen bond , ring (chemistry) , crystallography , chemistry , crystal structure , crystal (programming language) , group (periodic table) , stereochemistry , molecule , organic chemistry , computer science , programming language

The crystal structure of the title compound, C 11 H 12 N 4 , is stabilized by an N—H...N and three C—H...N intermolecular hydrogen bonds. The N—H...N hydrogen bonds generate centrosymmetric R 2 2 (6) rings, while the three C—H...N hydrogen bonds forms edge‐fused R 2 2 (7) R 2 2 (7) R 2 2 (10) ring motifs. Except for four H atoms of the methyl groups, all atoms are in the same plane and the dihedral angles between the aromatic and heterocyclic rings and the substituent group plane are 1.87 (5) and 1.53 (5)°, respectively.

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