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SN2 versus E2 Competition of Fand PH2Revisited
Author(s) -
Pascal Vermeeren,
Thomas Hansen,
Maxime Grasser,
Daniela Rodrigues Silva,
Trevor A. Hamlin,
F. Matthias Bickelhaupt
Publication year - 2020
Publication title -
the journal of organic chemistry
Language(s) - English
Resource type - Journals
SCImago Journal Rank - 1.2
H-Index - 228
eISSN - 1520-6904
pISSN - 0022-3263
DOI - 10.1021/acs.joc.0c02112
Subject(s) - sn2 reaction , chemistry , proton , nucleophile , competition (biology) , density functional theory , stereochemistry , base (topology) , computational chemistry , catalysis , biochemistry , physics , ecology , mathematical analysis , mathematics , biology , quantum mechanics
We have quantum chemically analyzed the competition between the bimolecular nucleophilic substitution (S N 2) and base-induced elimination (E2) pathways for F - + CH 3 CH 2 Cl and PH 2 - + CH 3 CH 2 Cl using the activation strain model and Kohn-Sham molecular orbital theory at ZORA-OLYP/QZ4P. Herein, we correct an earlier study that intuitively attributed the mechanistic preferences of F - and PH 2 - , i.e., E2 and S N 2, respectively, to a supposedly unfavorable shift in the polarity of the abstracted β-proton along the PH 2 - -induced E2 pathway while claiming that ″ ...no correlation between the thermodynamic basicity and E2 rate should be expected. ″ Our analyses, however, unequivocally show that it is simply the 6 kcal mol -1 higher proton affinity of F - that enables this base to engage in a more stabilizing orbital interaction with CH 3 CH 2 Cl and hence to preferentially react via the E2 pathway, despite the higher characteristic distortivity (more destabilizing activation strain) associated with this pathway. On the other hand, the less basic PH 2 - has a weaker stabilizing interaction with CH 3 CH 2 Cl and is, therefore, unable to overcome the characteristic distortivity of the E2 pathway. Therefore, the mechanistic preference of PH 2 - is steered to the S N 2 reaction channel (less-destabilizing activation strain).

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