Why Is Uranyl Formohydroxamate Red?
Author(s) -
Mark A. Silver,
Walter L. Dorfner,
Samantha K. Cary,
Justin N. Cross,
Jian Lin,
Eric J. Schelter,
Thomas E. AlbrechtSchmitt
Publication year - 2015
Publication title -
inorganic chemistry
Language(s) - English
Resource type - Journals
SCImago Journal Rank - 1.348
H-Index - 233
eISSN - 1520-510X
pISSN - 0020-1669
DOI - 10.1021/acs.inorgchem.5b00262
Subject(s) - uranyl , chemistry , crystallography , redox , solid state , bent molecular geometry , atomic orbital , inorganic chemistry , stereochemistry , ion , organic chemistry , quantum mechanics , electron , physics
The complexation of UO2(2+) by formohydroxamate (FHA(-)) creates solutions with dark red coloration. The inherent redox activity of formohydroxamate leads to the possibility that these solutions contain U(V) complexes, which are often red. We demonstrate that the reaction of U(VI) with formohydroxamate does not result in reduction, but rather in formation of the putative cis-aquo UO2(FHA)2(H2O)2, whose polymeric solid-state structure, UO2(FHA)2, contains an unusually bent UO2(2+) unit and a highly distorted coordination environment around a U(VI) cation in general. The bending of the uranyl cation results from unusually strong π donation from the FHA(-) ligands into the 6d and 5f orbitals of the U(VI) cation. The alteration of the bonding in the uranyl unit drastically changes its electronic and vibrational features.
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