Characterization of alkali induced formation of lanthionine, trisulfides, and tetrasulfides from peptide disulfides using negative ion mass spectrometry
Author(s) -
Suman S. Thakur,
P. Balaram
Publication year - 2009
Publication title -
journal of the american society for mass spectrometry
Language(s) - English
Resource type - Journals
SCImago Journal Rank - 0.961
H-Index - 127
eISSN - 1879-1123
pISSN - 1044-0305
DOI - 10.1016/j.jasms.2008.12.019
Subject(s) - chemistry , dehydroalanine , lanthionine , peptide , polysulfide , electrospray ionization , mass spectrometry , thiol , cyclic peptide , fragmentation (computing) , residue (chemistry) , stereochemistry , medicinal chemistry , organic chemistry , chromatography , biochemistry , electrode , computer science , electrolyte , operating system
Peptide disulfides are unstable under alkaline conditions, resulting in the formation of products containing lanthionine and polysulfide linkages. Electrospray ionization mass spectrometry has been used to characterize major species obtained when cyclic and acyclic peptide disulfides are exposed to alkaline media. Studies on a model cyclic peptide disulfide (Boc-Cys-Pro-Leu-Cys-NHMe) and an acyclic peptide, oxidized glutathione, bis ((gamma)Glu - Cys - Gly - COOH), are described. Disulfide cleavage reactions are initiated by the abstraction of C(alpha)H or C(beta)H protons of Cys residues, with subsequent elimination of H(2)S or H(2)S(2). The buildup of reactive thiol species which act on intermediates containing dehydroalanine residues, rationalizes the formation of lanthionine and polysulfide products. In the case of the cyclic peptide disulfide, the formation of cyclic products is facilitated by the intramolecular nature of the Michael addition reaction of thiols to the dehydroalanine residue. Mass spectral evidence for the intermediate species is presented by using alkylation of thiol groups as a trapping method. Mass spectral fragmentation in the negative ion mode of the peptides derived from trisulfides and tetrasulfides results in elimination of S(2).
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