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In this paper, we first give a necessary and sufficient condition for afactor code with an unambiguous symbol to admit a subshift of finite typerestricted to which it is one-to-one and onto. We then give a necessary andsufficient condition for the standard factor code on a spoke graph to admit asubshift of finite type restricted to which it is finite-to-one and onto. Wealso conjecture that for such a code, this finite-to-one property is equivalentto the existence of a stationary Markov chain that achieves the capacity of thecorresponding deterministic channel.

Markov Capacity for Factor Codes with an Unambiguous Symbol