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The aim of this paper is to find a general formula to generate any row ofPascal's triangle as an extension of the concept of $\left(11\right)^{n}$. Inthis study, the visualization of each row of Pascal's triangle has beenpresented by extending the concept of the power of 11 to the power of 101,1001, 10001, and so on. We briefly discuss how our proposed concept works forany $n$ by inserting an appropriate number of zeros between $1$ and $1$(eleven), that is the concept of $\left(11\right)^{n}$ has been extended to$\left(1\Theta1\right)^{n}$, where $\Theta$ represents the number of zeros. Wehave proposed a formula for obtaining the value of $\Theta$. The proposedconcept has been verified with Pascal's triangle and matched successfully.Finally, Pascal's triangle for a large n has been presented considering the$51^{\text{st}}$ row as an example.

Binomial Coefficients in a Row of Pascal's Triangle from Extension of Power of Eleven: Newton's Unfinished Work