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A quantum field theory has finite zero-point energy if the sum over all bosonmodes $b$ of the $n$th power of the boson mass $ m_b^n $ equals the sum overall fermion modes $f$ of the $n$th power of the fermion mass $ m_f^n $ for $n=0$, 2, and 4. The zero-point energy of a theory that satisfies these threeconditions with otherwise random masses is huge compared to the density of darkenergy. But if in addition to satisfying these conditions, the sum of $m_b^4\log m_b/\mu$ over all boson modes $b$ equals the sum of $ m_f^4 \log m_f/\mu $over all fermion modes $f$, then the zero-point energy of the theory is zero.The value of the mass parameter $\mu$ is irrelevant in view of the thirdcondition ($n=4$).  The particles of the standard model do not remotely obey any of these fourconditions. But an inclusive theory that describes the particles of thestandard model, the particles of dark matter, and all particles that have notyet been detected might satisfy all four conditions if pseudomasses areassociated with the mean values in the vacuum of the divergences of theinteractions of the inclusive model. Dark energy then would be the finitepotential energy of the inclusive theory.

Zero-point energies, dark matter, and dark energy