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Let integer be any C/C++ unsigned integer type up to 64-bits long. Given aDyck word the following code returns the next Dyck word of the same size,provided it exists.  integer next_dyck_word(integer w) {  integer const a = w & -w;  integer const b = w + a;  integer c = w ^ b;  c = (c / a >> 2) + 1;  c = ((c * c - 1) & 0x) | b;  return c;  }

A loopless and branchless $O(1)$ algorithm to generate the next Dyck word