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Given $\beta\in(1,2)$ and $x\in[0,\frac{1}{\beta-1}]$, a sequence$(\epsilon_{i})_{i=1}^{\infty}\in\{0,1\}^{\mathbb{N}}$ is called a$\beta$-expansion for $x$ if$$x=\sum_{i=1}^{\infty}\frac{\epsilon_{i}}{\beta^{i}}.$$ In a recent articlethe author studied the quality of approximation provided by the finite sums$\sum_{i=1}^{n}\epsilon_{i}\beta^{-i}$ \cite{Bak}. In particular, given$\beta\in(1,2)$ and $\Psi:\mathbb{N}\to\mathbb{R}_{\geq 0},$ we associate theset$$W_{\beta}(\Psi):=\bigcap_{m=1}^{\infty}\bigcup_{n=m}^{\infty}\bigcup_{(\epsilon_{i})_{i=1}^{n}\in\{0,1\}^{n}}\Big[\sum_{i=1}^{n}\frac{\epsilon_{i}}{\beta^{i}},\sum_{i=1}^{n}\frac{\epsilon_{i}}{\beta^{i}}+\Psi(n)\Big].$$Alternatively, $W_{\beta}(\Psi)$ is the set of $x\in \mathbb{R}$ such that forinfinitely many $n\in\mathbb{N},$ there exists a sequence$(\epsilon_{i})_{i=1}^{n}$ satisfying the inequalities $$0\leqx-\sum_{i=1}^{n}\frac{\epsilon_{i}}{\beta^{i}}\leq \Psi(n).$$ If$\sum_{n=1}^{\infty}2^{n}\Psi(n)<\infty$ then $W_{\beta}(\Psi)$ has zeroLebesgue measure. We call a $\beta\in(1,2)$ approximation regular, if$\sum_{n=1}^{\infty}2^{n}\Psi(n)=\infty$ implies $W_{\beta}(\Psi)$ is of fullLebesgue measure within $[0,\frac{1}{\beta-1}]$. The author conjectured in\cite{Bak} that almost every $\beta\in(1,2)$ is approximation regular. In thispaper we make a significant step towards proving this conjecture.  The main result of this paper is the following statement: given a sequence ofpositive real numbers $(\omega_{n})_{n=1}^{\infty},$ which satisfy$\lim_{n\to\infty} \omega_{n}=\infty$, then for Lebesgue almost every$\beta\in(1.497\ldots,2)$ the set $W_{\beta}(\omega_{n}\cdot 2^{-n})$ is offull Lebesgue measure within $[0,\frac{1}{\beta-1}]$. Here the sequence$(\omega_{n})_{n=1}^{\infty}$ should be interpreted as a sequence tending toinfinity at a very slow rate.

Approximation properties of $\beta$-expansions II