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New data analysis with Pauli blocking and entanglement explains CP violationin $B^o\rightarrow K\pi$ decays, absence in $B^{\pm} \rightarrow K\pi$ decaysand predicts unexpected contrast between pure I=1/2 in individual $B^{\pm}$ and$B^o$ final states and I=1/2 violation in relations between them. Analysis of$B\rightarrow K\pi$ data predicts these observed isospin relations and explainsdependence on spectator quark flavor. $B^+ \rightarrow K\pi$ tree diagram $\barb u\rightarrow \bar s u \bar u u$ has two identical $u$ quarks from weak vertexand spectator. The Pauli principle requires these quarks at short distances tohave wave functions antisymmetric in color or spin. The eigenvalues ofconserved symmetries remain entangled in a final state of two separated mesons.This Pauli entanglement suppresses tree-penguin interference and CP violationin $B^+$ decay but not in $B^o$ decay with spectator $d$ quark.  The four-body wave function must have two antiquarks with the same symmetrycombining with two u-quarks to fragment into a two-pseudoscalar-meson stateeven under charge conjugation with angular momentum zero. It is classified inthe 27-dimensional representation of flavor SU(3) with isospin I=2 for the $\pi\pi$ state and V spin V=2 for the corresponding strange state which is linearcombination of $K\pi$ and $K\eta_8$. These symmetries remain entangled infour-body wave function even after separation into two mesons. Strong Paulisuppression in tree transitions to $K\pi$ which has only a small V=2 componentand is mainly V=1. No Pauli suppression in transitions to I=2 $\pi \pi$ statewith also two $u$ quarks but different color-spin couplings. Standarddefinition of independent color favored and suppressed tree diagrams in$B^\pm\rightarrow K\pi$ decays neglects $uu$ Pauli entanglement.

Pauli blocking and entanglement solve $K\pi$ puzzle. CP violation in $B^o \rightarrow K\pi$; not in $B^{\pm} \rightarrow K\pi$decays