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The heat of combustion of liquid borazine has been determined according to the following equation:B  3    N  3    H  6    (   liq   )   +  15  /  4O  2    (  g  )   +  3  /  2H  2   O(   liq   )   =  3   H  3    BO  3    (  c  )   +  3  /  2   N  2    (  g  )   ,Δ  H  °   (   25  °  C   )   =  -  2313.3  ±  12.6    kj  /  mole(   -  552.90  ±  3.0    kcal  /  mole   )   .From this value the heat of formation of liquid borazine may be calculated as Δ Hf° (25 °C) = -548.5 ± 13.4 kj/mole (-131.1 ± 3.2 kcal/mole), and for the gas, Δ Hf° (25 °C) = -519.2 ± 13.4 kj/mole (-124.1 ± 3.2 kcal/mole).

Heat of combustion of borazine, B3N3H6