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The crystal structure of Rb 2 [(+)-C 4 H 4 O 6 ] has been determined at room temperature by X-ray diffraction. The compound crystalizes in the space group  P 3 2 21 with  a  = 7.158(4) Å,  c  = 13.087(2) Å,  V  = 580.7 Å 3 ,  D c   = 2.737  Mgm  −3 ,  Z  = 3. The structure has been solved by Patterson and Fourier methods and refined by least-squares calculations to a final R value of 0.040 for 386 reflexions [| F  0 | ≥ 4 σ ( F 0)].

Die Kristallstruktur von Rubidiumtartrat Rb 2 [(+) – C 4 H 4 O 6 ]