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Single crystals of Sm 2 Pt 6 P 3  (a = 4.095(1), c = 45.313(9) Å ) were prepared by heating the elements in a melt of NaCl/KCl at 1100°C. The compound crystallizes with a new tetragonal type of structure (I4 1 /amd; Z = 4) consisting of units which correspond to the CaBe 2 Ge 2  type except for one significant difference: In the layer of PPt 4  tetrahedra only two of four P positions are occupied. Therefore this layer is built up by corner- instead of edge-sharing PPt 4  tetrahedra. Four of these units are stacked along [001]. Single crystals of Ca 2 Pd 3 Sb 4  (a = 4.506(1), c = 41.538(8) Å ) were obtained by reaction of the elements at 900°C. The crystal structure (I4/mmm; Z = 4) consists of two blocks. The first one has the composition CaPd 2 Sb 3  and can be derived from the CaBe 2 Ge 2  type. In the second one (formula CaPdSb) the atoms are arranged analogous to the CeMg 2 Si 2  type. Both blocks alternate along [001]

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Kristallstrukturen mit Bausteinen des CaBe 2 Ge 2 -Typs – Die Verbindungen Sm 2 Pt 6 P 3  und Ca 2 Pd 3 Sb 4  / Crystal Structures with CaBe 2 Ge 2 -Type Units – The Compounds Sm 2 Pt 6 P 3  and Ca 2 Pd 3 Sb 4