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The boron hydride B 4 H 10  is prepared in high yields (90%) through hydride-ion abstraction reactions when a mixture of BH 4  - /B 4 H 8  -  is treated with CH 3 I or I 2  respectively. A high yield (96%) method for the conversion of B 3 H 8  to B 4 H 10  is the reaction of B 3 H 8  -  with AICl 3  solvents which do not have any Lewis base character. The solvents are assumed to react as electron acceptors with the intermediate [B 2 H 5  - ] to form B 4 H 10 , R -  and H 2  (R-H = solvent). A 1:1 mixture of B 4 H 10 , and B 5 H 9  is obtained when B 3 H 8  -  is treated with CH 3 I or I 2 . The reaction can be viewed to involve an initial step in which unstable “B 3 H 7 ” is generated which immediately undergoes decomposition to give B 4 H 10 , B 5 H 9  and H 2 . Treatment of B 4 H 10  with (n-Bu) 4 NBr results in the formation of B 4 H 7 Br -  which decomposes slowly at 0 °C to form B 5 H 9 . An alternative synthesis of B 5 H 9 , via hydride-ion abstraction is possible through the reaction of (n-Bu) 2 O-BF 4  with B 3 H 8  -  in ether solvents.

Neue Synthesewege zu B 4 H 10 und B 5 H 9 / New Synthetic Routes to B 4 H 10 and B 5 H 9