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Bis(tetrapropylammonium)heptasulfide results from the reaction of [(C 3 H 7 ) 4 N]Br and Na 2 S 5  (molar ratio 4:1 to 2:1) in aqueous solution. The dark orange compound crystallizes in the space group P2 1 /c, the lattice constants are (at -70 °C): a = 9.466(4) Å , b = 11.013(3) Å, c = 16.845(7) Å , β = 105.6(1)°. It contains unbranched chainlike S 7  2−  anions of all-trans-conformation.

zeitschrift für naturforschung b

Die Kristallstruktur des Bis(tetrapropylammonium)heptasulfids [N(C 3 H 7 ) 4 ] 2 S 7  / The Crystal Structure of Bis(tetrapropylammonium)heptasulfide [N(C 3 H 7 ) 4 ] 2 S 7