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The reaction of MeAlCl2 with EtOH (1:1) yields [(Cl2Al)3^-OEt)6Al] via EtOAlCl2 as an intermediate. The aluminum compound containing a six-coordinated aluminum atom was characterized by NMR and its structure was determined by X-ray analysis.

REACTION OF MeAlCl2 WITH ETHYL ALCOHOL (1:1) LEADING TO [(Cl2Al)3(μ-OEt)6Al]