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We consider the Diophantine equation x2-kxy+ky2+ ly = 0 for l = 2n and determine for which values of the odd integer k, it has a positive integer solution x and y

On the Diophantine Equation x2 – kxy + ky2 + ly = 0, l = 2n

On the Diophantine Equation x² – kxy + ky² + ly = 0, l = 2ⁿ