English (United Kingdom)

https://curated-unify.zendy.io/wp-json/zendy-region/v1/featured_content/oa?rat=en

https://curated-unify.zendy.io/wp-json/zendy-region/v1/highlighted_journal/

Global: Zendy Tools annual

Presents the keyphrase highlighting as premium feature

Keyphrase Highlighting

Presents the summarisation as premium feature

Summarisation

Insights

Presents the pdf analysis as premium feature

PDF Analysis

Presents the zaia usage as premium feature

ZAIA

Global: Zendy Tools monthly

Global: Zendy Plus monthly

Presents the access of premium content as premium feature

Premium Content

Global: Zendy Plus annual

Global: Zendy Free Plan

Consider the matrixn = (( I(Xi + Xj > 0) ))i,j=1,2,...,n where {Xi} are i.i.d. and their distribution is continuous and symmetric around 0. We show that the rank rn of this matrix is equal in distribution to 2 P n 1 i=1 I(i = 1,i+1 = 0) + I(n = 1) wherei i.i.d.  Ber(1,1/2). As a consequence p n(rn/n 1/2) is asymptotically normal with mean zero and variance 1/4. We also show that n 1rn converges to 1/2 almost surely.

On asymptotic properties of the rank of a special random adjacency matrix