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Let Hn=∑r=1n1/r$H_{n} = \sum_{r=1}^{n} 1/r$ and Hn(x)=∑r=1n1/(r+x)$H_{n}(x) = \sum_{r=1}^{n} 1/(r+x)$. Let ψ(x)$\psi(x)$ denote the digamma function. It is shown that Hn(x)+ψ(x+1)$H_{n}(x) + \psi(x+1)$ is approximated by 12logf(n+x)$\frac{1}{2}\log f(n+x)$, where f(x)=x2+x+13$f(x) = x^{2} + x + \frac{1}{3}$, with error term of order (n+x)−5$(n+x)^{-5}$. The cases x=0$x = 0$ and n=0$n = 0$ equate to estimates for Hn−γ$H_{n} - \gamma $ and ψ(x+1)$\psi(x+1)$ itself. The result is applied to determine exact bounds for a remainder term occurring in the Dirichlet divisor problem.

A logarithmic estimate for harmonic sums and the digamma function, with an application to the Dirichlet divisor problem