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The recent advent of experimental techniques in which the dynamicalcharacteristics of fission fragments are determined more accurately, promptedus to investigate the angular momentum acquired by fragments in a model whichdescribes the cold(neutronless) fission of $^{252}$Cf as the decay of a giantnuclear molecule. The molecular configuration is a consequence of the interplaybetween the attractive nuclear part and the repulsive Coulomb+nuclear forces.The basic ideea of the present approach is to separate the radial(fission)modes describing the decay of the molecule from the modes associated totransversal vibrations(bending) of the fragments. The distance between thecenters of the two fragments is fixed by the requirement that the energyreleased in the fission reaction $Q$, equals the sum of quantum zero-energiesof radial and transversal modes and the total excitation energy $E^*$. Using asemiclassical coupled channel formalism we computed the additional angularmomenta acquired by the fragments during their post-scission motion, and foundthat the Coulomb excitation accounts for less than 10% of the final spins.Comment: 6 page

physical review. c. nuclear physics/physical review. c, nuclear physics

Angular momenta of even-even fragments in the neutronless fission of<mml:math xmlns:mml="http://www.w3.org/1998/Math/MathML" display="inline"><mml:mrow><mml:msup><mml:mrow /><mml:mrow><mml:mn>252</mml:mn></mml:mrow></mml:msup></mml:mrow><mml:mi mathvariant="normal">Cf</mml:mi></mml:math>

Angular momenta of even-even fragments in the neutronless fission of252Cf