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Neutron diffraction and magnetic susceptibility studies show thatorthorhombic single-crystals of topological semimetals ${\rmSr(Mn_{0.9}Cu_{0.1})Sb_2}$ and ${\rm Sr(Mn_{0.9}Zn_{0.1})Sb_2}$ undergo threedimensional C-type antiferromagnetic (AFM) ordering of the Mn$^{2+}$ moments at$T_N = 200\pm10$ and $210\pm12$ K, respectively, significantly lower than thatof the parent SrMnSb$_2$ with $T_N=297 \pm 3$ K. Magnetization versus appliedmagnetic field (perpendicular to MnSb planes) below $T_N$ exhibits slightlymodified de Haas van Alphen oscillations for the Zn-doped crystal as comparedto that of the parent compound. By contrast, the Cu-doped system does not showde Haas van Alphen magnetic oscillations, suggesting that either Cusubstitution for Mn changes the electronic structure of the parent compoundsubstantially, or that the Cu sites are strong scatterers of carriers thatsignificantly shorten their mean free path thus diminishing the oscillations.Density functional theory (DFT) calculations including spin-orbit couplingpredict the C-type AFM state for the parent, Cu-, and Zn-doped systems andidentify the $a$-axis (i.e., perpendicular to the Mn layer) as the easymagnetization direction in the parent and 12.5% of Cu or Zn substitutions. Incontrast, 25% of Cu content changes the easy magnetization to the $b$-axis(i.e., within the Mn layer). We find that the incorporation of Cu and Zn inSrMnSb$_2$ tunes electronic bands near the Fermi level resulting in differentband topology and semi-metallicity. The parent and Zn-doped systems havecoexistence of electron and hole pockets with opened Dirac cone around theY-point whereas the Cu-doped system has dominant hole pockets around the Fermilevel with a distorted Dirac cone. The tunable electronic structure may pointout possibilities of rationalizing the experimentally observed de Haas vanAlphen magnetic oscillations.

physical review. b./physical review. b

Controlling Magnetic Order, Magnetic Anisotropy, and Band Topology in  Semimetals ${\rm Sr(Mn_{0.9}Cu_{0.1})Sb_2}$ and ${\rm  Sr(Mn_{0.9}Zn_{0.1})Sb_2}$