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We prove Laporta's conjecture\begin{align*}&\int_0^\infty\frac{\mathrm d\,x_1}{x_1}\int_0^\infty\frac{\mathrm d\, x_2}{x_2}\int_0^\infty\frac{\mathrm d\,x_3}{x_3}\int_0^\infty\frac{\mathrm d\,x_4}{x_4}\frac{1}{\left(1+\sum^4_{k=1}x_k\right)\left(1+\sum^4_{k=1}\frac{1}{x_{k}}\right)-1}\\={}&\frac43 \int_{0}^\pi\mathrm d\, \phi_1 \int_{0}^\pi\mathrm d\,\phi_2\int_{0}^\pi\mathrm d\, \phi_3 \int_{0}^\pi\mathrm d\,\phi_4\frac{1}{4-\sum_{k=1}^4\cos \phi_k}, \end{align*} which relates the4-loop sunrise diagram in 2-dimensional quantum field theory to Watson'sintegral for 4-dimensional hypercubic lattice. We also establish severalrelated integral identities proposed by Laporta, including a reduction of the4-loop sunrise diagram to special values of Euler's gamma function andgeneralized hypergeometric series:\begin{align*} \frac{4 \pi^{5/2}}{\sqrt{3}}\left\{ \frac{\sqrt{3} }{2^6 }\left[\frac{\Gamma\left(\frac{1}{3}\right)}{\sqrt{\pi}}\right]^9\, _4F_3\left(\left.\begin{array}{c}\frac{1}{6},\frac{1}{3},\frac{1}{3},\frac{1}{2}\\[4pt]\frac{2}{3},\frac{5}{6},\frac{5}{6}\end{array}\right|1\right)-\frac{2^{4}}{3}\left[\frac{\sqrt{\pi}}{\Gamma\left(\frac{1}{3}\right)}\right]^9\, _4F_3\left(\left.\begin{array}{c}\frac{1}{2},\frac{2}{3},\frac{2}{3},\frac{5}{6}\\[4pt]\frac{7}{6},\frac{7}{6},\frac{4}{3}\end{array}\right|1\right) \right\}. \end{align*}

On Laporta's 4-loop sunrise formulae